10x^2+9x+20/5

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Solution for 10x^2+9x+20/5 equation:


x in (-oo:+oo)

10*x^2+9*x+20/5 = 0

10*x^2+9*x+4 = 0

DELTA = 9^2-(4*4*10)

DELTA = -79

DELTA < 0

x belongs to the empty set

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